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In Cu-ammonia complex, the state of hybridization of Cu+2 is (A) sp3 (B) d3 s (C) sp2 f (D) dsp2

In Cu-ammonia complex, the state of hybridization of Cu+2 is
(A) sp3 (B) d3
s (C) sp2
f (D) dsp2

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2 Answers

Saurabh Koranglekar
askIITians Faculty 10335 Points
3 years ago
Dear student

The answer is option d


Regards
Vikas TU
14149 Points
3 years ago
According Valence Bond Theory Cu2+ has the configuration [Ar]3d9 plus the vacant 4s and 4p orbitals. These vacant orbitals accommodate electrons (lone pairs) from four ammine ligands thus forming [Cu(NH3)4]2+. The hybridization is sp3.

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