If a, ß are the roots of the quadratic equation x2+ax+b=0, (b?0); then the quadratic equation whose roots are

a - 1 , ß - 1 is
ß a

(A) ax2+a(b–1)x+(a–1)2=0 (B) bx2+a(b–1)x+(b–1)2=0 (C) x2+ax+b = 0 (D) abx2+bx+a = 0

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Saurabh Koranglekar · Answer

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If a, ß are the roots of the quadratic equation x2+ax+b=0, (b?0); then the quadratic equation whose roots are a - 1 , ß - 1 is ß a (A) ax2+a(b–1)x+(a–1)2=0 (B) bx2+a(b–1)x+(b–1)2=0 (C) x2+ax+b = 0 (D) abx2+bx+a = 0

If a, ß are the roots of the quadratic equation x2+ax+b=0, (b?0); then the quadratic equation whose roots are

a - 1 , ß - 1 is
ß a

(A) ax2+a(b–1)x+(a–1)2=0 (B) bx2+a(b–1)x+(b–1)2=0 (C) x2+ax+b = 0 (D) abx2+bx+a = 0

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If a, ß are the roots of the quadratic equation x2+ax+b=0, (b?0); then the quadratic equation whose roots are a - 1 , ß - 1 is ß a (A) ax2+a(b–1)x+(a–1)2=0 (B) bx2+a(b–1)x+(b–1)2=0 (C) x2+ax+b = 0 (D) abx2+bx+a = 0

If a, ß are the roots of the quadratic equation x2+ax+b=0, (b?0); then the quadratic equation whose roots are a - 1 , ß - 1 is ß a (A) ax2+a(b–1)x+(a–1)2=0 (B) bx2+a(b–1)x+(b–1)2=0 (C) x2+ax+b = 0 (D) abx2+bx+a = 0

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If a, ß are the roots of the quadratic equation x2+ax+b=0, (b?0); then the quadratic equation whose roots are

a - 1 , ß - 1 is
ß a

(A) ax2+a(b–1)x+(a–1)2=0 (B) bx2+a(b–1)x+(b–1)2=0 (C) x2+ax+b = 0 (D) abx2+bx+a = 0