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Engineering Entrance Exams

For making distinction between 2-pentanone and 3-pentanone the reagent to be employed is (A) K2 Cr2 O7 /H2 SO4 (B) Zn-Hg/HCl (C) SeO2 (D) Iodine/NaOH

Profile image of aniket anand
12 Years agoGrade
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2 Answers

Profile image of Saurabh Koranglekar
6 Years ago
Dear student

The answer is option d

Regards
Profile image of Vikas TU
6 Years ago
For making distinction between 2 pentanone and 3 pentanone the reagent to be employed is. Iodine and NaOH. Solution : Acetophenone reacts with iodine and NaOH to form iodoform.

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