Thank you for registering.

One of our academic counsellors will contact you within 1 working day.

Please check your email for login details.
MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping

For a chemical reaction at 27°C, the activation energy is 600 R. The ratio of the rate constants at 327°C to that of at 27°C will be (A) 2 (B) 40 (C) e (D) e2

For a chemical reaction at 27°C, the activation energy is 600 R. The ratio of the rate constants at 327°C to that of at
27°C will be
(A) 2 (B) 40 (C) e (D) e2

Grade:

2 Answers

Saurabh Koranglekar
askIITians Faculty 10341 Points
one year ago
Dear student

The answer is option c

Regards
Vikas TU
14149 Points
one year ago
The ratio of rate constants at 327° C to that at 27° C is e.
Given-
Activation energy of the chemical reaction = 600 R
Initial temperature (T₁) = 27° C = 300 K
Final temperature (T₂) = 327° C = 600 K
From the Arrhenius equation we can find out the ratio of rate constants -
ln ( K₂/K₁)  = Ea / R (1/T₁ - 1/T₂) ,
where Ea is the activation energy, R is the universal gas constant, K₁ is the rate constant at temperature T₁, and K₂ is the rate constant at temperature T₂.
Now by putting the values we get -
ln ( K₂/K₁) = 600 R/R ( 1/300 - 1/600)
ln ( K₂/K₁)  = 600 ( 2-1/600)
ln ( K₂/K₁)  = 1
So,  K₂/K₁ = e¹ = e
Hence ratio of rate constants is e .
 

Think You Can Provide A Better Answer ?

Provide a better Answer & Earn Cool Goodies See our forum point policy

ASK QUESTION

Get your questions answered by the expert for free