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At 800C, the vapour pressure of pure liquid 'A' is 520 mm Hg and that of pure liquid 'B' is 1000 mm Hg. If a mixture solution of 'A' and 'B' boils at 800C and 1 atm pressure, the amount of 'A' in the mixture is (1 atm = 760 mm Hg) i. 48 mol percent ii. 50 mol percent iii. 52 mol percent iv. 34 mol percent

At 800C, the vapour pressure of pure liquid 'A' is 520 mm Hg and that of pure liquid 'B' is 1000 mm Hg. If a
mixture solution of 'A' and 'B' boils at 800C and 1 atm pressure, the amount of 'A' in the mixture is (1 atm = 760 mm
Hg)
i. 48 mol percent
ii. 50 mol percent
iii. 52 mol percent
iv. 34 mol percent

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2 Answers

Saurabh Koranglekar
askIITians Faculty 10336 Points
2 years ago
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Vikas TU
14149 Points
2 years ago
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Dear student 
Please refer the clear image , 
The image above does not looks good , it is blurr.
Hope for the best 
Good Luck 
Cheers 

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