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# Assume that a drop of liquid evaporates by decrease in its surface energy, so that its temperature remains unchanged. What should be the minimum radius of the drop for this to be possible? The surface tension is T, density of liquid is ? and L is its latent heat of vaporization.

Grade:11

## 2 Answers

Saurabh Koranglekar
askIITians Faculty 10341 Points
11 months ago
Vikas TU
14149 Points
11 months ago
When radius is by ∆R,
4πR2∆RpL = 4πT[R2 – (R - ∆R]
$\Rightarrow$pR2∆RL = T[R2 – R2 + 2R∆R - ∆R2]
$\Rightarrow$pR2∆RL =T2R∆R [ ∆R is very small ]
$\Rightarrow$R = 2T/pL

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