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Grade 11Engineering Entrance Exams

Assume that a drop of liquid evaporates by decrease in its surface energy, so that its temperature remains unchanged. What should be the minimum radius of the drop for this to be possible? The surface tension is T, density of liquid is ? and L is its latent heat of vaporization.

Profile image of Jayant Kumar
12 Years agoGrade 11
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2 Answers

Profile image of Saurabh Koranglekar
6 Years ago
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Profile image of Vikas TU
6 Years ago
When radius is by ∆R,
4πR2∆RpL = 4πT[R2 – (R - ∆R]
\RightarrowpR2∆RL = T[R2 – R2 + 2R∆R - ∆R2]
\RightarrowpR2∆RL =T2R∆R [ ∆R is very small ]
\RightarrowR = 2T/pL

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