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In BCC (Body Centred Cubic Crystal), distance between any two nearest atoms is
(a) √3a
(b) √3/2 a
(c) √3/4 a
(d) a/2

Hrishant Goswami , 11 Years ago
Grade 10
anser 1 Answers
Amit Saxena

Last Activity: 11 Years ago

(b)

Atom at corner are shared by 8 cubes. Atom belonging to one cube = - 8 = 1

Atom at centre belongs to only one cube. Hence, total number of atoms belonging to one cube = 2.

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