Thank you for registering.

One of our academic counsellors will contact you within 1 working day.

Please check your email for login details.
MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping

In BCC (Body Centred Cubic Crystal), distance between any two nearest atoms is (a) √3a (b) √3/2 a (c) √3/4 a (d) a/2

In BCC (Body Centred Cubic Crystal), distance between any two nearest atoms is    
    (a)    √3a
    (b)    √3/2 a
    (c)    √3/4 a
    (d)    a/2

Grade:10

1 Answers

Amit Saxena
35 Points
7 years ago

(b)

Atom at corner are shared by 8 cubes. Atom belonging to one cube = - 8 = 1

Atom at centre belongs to only one cube. Hence, total number of atoms belonging to one cube = 2.

Think You Can Provide A Better Answer ?

Provide a better Answer & Earn Cool Goodies See our forum point policy

ASK QUESTION

Get your questions answered by the expert for free