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In BCC (Body Centred Cubic Crystal), distance between any two nearest atoms is (a) √3a (b) √3/2 a (c) √3/4 a (d) a/2

In BCC (Body Centred Cubic Crystal), distance between any two nearest atoms is    
    (a)    √3a
    (b)    √3/2 a
    (c)    √3/4 a
    (d)    a/2

Grade:10

1 Answers

Amit Saxena
35 Points
8 years ago

(b)

Atom at corner are shared by 8 cubes. Atom belonging to one cube = - 8 = 1

Atom at centre belongs to only one cube. Hence, total number of atoms belonging to one cube = 2.

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