Adarsh8 Years agoWork done by rotating electric dipole = -pEs[cos@]0180 = 0 .Hope this will help you Thanks and Regards Adarsh
Khimraj8 Years agowork done in rotating electric dipole = pEsindW = -pE[cos]0180 = -pE(-1-1) = 2pE.Hope it clears. If you like answer then please approve it.