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what is percentage change in distance if the force of attraction between two point charges increases to 4 times keeping of charges constant?

vaibhav jain , 9 Years ago
Grade 12
anser 1 Answers
Narendran
As,
F\alpha \frac{1}{r^{2}}.
 
r\alpha \frac{1}{\sqrt{F}}.
 
there for  reduces to half as F goes upto 4 times.Hence the percentage change is -50% (reduces).
Last Activity: 9 Years ago
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