Question icon
Grade Upto college level Electrostatics

Two solenoids each of length L are wound over each other. A1 and A2are the areas of the outer and inner solenoids and N1and N2 are the no. of turns per unit length of the two solenoids. Writethe expressions for the self inductances of the two solenoids and their mutual inductance. Hence show that square of the mutual inductance of the two solenoids is less than the product of the self inductances of the two solenoids.

Profile image of Manvendra Singh chahar
12 Years agoGrade Upto college level
Answers icon

1 Answer

Profile image of Askiitians Tutor Team
ApprovedApproved Tutor Answer1 Year ago

To tackle the problem of two solenoids wound over each other, we need to derive the expressions for their self-inductances and mutual inductance. Let's break this down step by step, starting with the definitions and formulas involved.

Self-Inductance of Solenoids

The self-inductance \( L \) of a solenoid can be expressed using the formula:

L = \frac{\mu_0 N^2 A}{L}

Where:

  • \( \mu_0 \) is the permeability of free space (approximately \( 4\pi \times 10^{-7} \, \text{H/m} \))
  • N is the number of turns of the solenoid
  • A is the cross-sectional area of the solenoid
  • L is the length of the solenoid

For the two solenoids, we can denote their self-inductances as follows:

Self-Inductance of the Outer Solenoid

The self-inductance \( L_1 \) of the outer solenoid can be expressed as:

L_1 = \frac{\mu_0 N_1^2 A_1}{L}

Self-Inductance of the Inner Solenoid

Similarly, the self-inductance \( L_2 \) of the inner solenoid is given by:

L_2 = \frac{\mu_0 N_2^2 A_2}{L}

Mutual Inductance of the Solenoids

The mutual inductance \( M \) between two solenoids can be defined as:

M = k \sqrt{L_1 L_2}

Where \( k \) is the coupling coefficient, which ranges from 0 to 1, depending on how well the magnetic fields of the solenoids interact. For tightly wound solenoids, \( k \) approaches 1.

Deriving the Relationship

Now, let's derive the relationship that shows the square of the mutual inductance is less than the product of the self-inductances:

From the expressions we derived:

M^2 = k^2 L_1 L_2

Since \( k \) is a coefficient that is less than or equal to 1, we can say:

M^2 \leq L_1 L_2

This inequality indicates that the square of the mutual inductance \( M^2 \) is indeed less than or equal to the product of the self-inductances \( L_1 \) and \( L_2 \). This relationship is fundamental in electromagnetic theory and highlights the limitations of mutual coupling between inductors.

Conclusion

In summary, we derived the self-inductances of the two solenoids as \( L_1 \) and \( L_2 \), and the mutual inductance \( M \) between them. The relationship \( M^2 \leq L_1 L_2 \) emphasizes that the mutual inductance cannot exceed the product of the individual self-inductances, which is a crucial concept in understanding inductive coupling in electrical circuits.