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`        two point charges one at x=3m and other at x=-3m.A third charge of mass m and charge -Q is released from rest at y=4m. Find the speed of the particle when it reaches the origin`
one year ago

Kapil Khare
80 Points
```							Let the speed of the particle be v when it reaches the origin.Let the charge of point charges be q.Uinitial = (-KQq/5) + (-KQq/5) + (Kq2/6)          = (-2KQq/5) + (Kq2/6)Ufinal = (-KQq/3) + (-KQq/3) + (Kq2/6) + (mv2/2)         = (-2KQq/3) + (Kq2/6) + (mv2/2)We know that,                                 Uinitial = Ufinal$\implies$   (-2KQq/5) + (Kq2/6) = (-2KQq/3) + (Kq2/6) + (mv2/2)$\implies$                      (mv2/2) = (2KQq/3) + (-2KQq/5)$\implies$                      (mv2/2) = (4KQq/15)$\implies$                               v = (8KQq/15m)½ Thus speed of particle on reaching origin is (8KQq/15m)½.
```
one year ago
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• 110 Video Lectures
• Revision Notes
• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions