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two parallel plates (each of area 200cm2) of a capacitor are given equal and opposite charge of magnitude 1.75microC.The space between the plates is filled with dielectric.If the electric field in the dielectric is 1.5*10^6 V/m what will be the magnitude of chare induced on each dielectric plate
Q=1.75microC=1.75×10-6CA=200cm2=200×10-4 m2€o=8.854×10-12 F/mEo=Q/A€o=9.8×106V/mEp=1.5×106V/mE=Eo-Ep=8.3×106 V/mEo=kEor,k=Eo/E=1.18Induced charge Q'=(k-1)Q/k=0.266 micro C Hope it helps RegardsArun
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