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two molecules each wtih permanent dipole moment p are aligned as shown. calculate the force between the molecules if they are separated by a distance that is large compared with the dimension of the diples.(hint:the relation(1+x)^-2=1-2x+3x^2-........for small x is useful)

Animesh Kerketta , 8 Years ago
Grade 12
anser 3 Answers
Rohit

Last Activity: 6 Years ago

Electric field on one due to other is
E = k2p/r3 
So force F = p dE/dr
F -6Kp2/r4
I .think it will be helpful. 
Khimraj

Last Activity: 6 Years ago

To find the force on one dipole due to another dipole, we have to find the electric field at the second dipole due to the first dipole. Therefore,
E=2kPr3
So, force on the second dipole due to this field is,
F⃗ =P2 (dE1dr)iˆ=P(−6kPr4) iˆ⇒∣∣ F⃗ ∣∣=−6kP2r4
Here, the negative sign indicates, the force will be attractive in nature.
SWAYAM PRAKASH MALIK

Last Activity: 4 Years ago

Electric field on one molecule due to the other is
E = k2p/r3 
So force F = p * dE/dr
F  = P ( -6k / r^4 ) .
Here the force is attractive , So it is negative.
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