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# two molecules each wtih permanent dipole moment p are aligned as shown. calculate the force between the molecules if they are separated by a distance that is large compared with the dimension of the diples.(hint:the relation(1+x)^-2=1-2x+3x^2-........for small x is useful)

Rohit
11 Points
2 years ago
Electric field on one due to other is
E = k2p/r3
So force F = p dE/dr
F -6Kp2/r4
I .think it will be helpful.
Khimraj
3007 Points
2 years ago
To find the force on one dipole due to another dipole, we have to find the electric field at the second dipole due to the first dipole. Therefore,
E=2kPr3
So, force on the second dipole due to this field is,
F⃗ =P2 (dE1dr)iˆ=P(−6kPr4) iˆ⇒∣∣ F⃗ ∣∣=−6kP2r4
Here, the negative sign indicates, the force will be attractive in nature.
SWAYAM PRAKASH MALIK
36 Points
one month ago
Electric field on one molecule due to the other is
E = k2p/r3
So force F = p * dE/dr
F  = P ( -6k / r^4 ) .
Here the force is attractive , So it is negative.