Two identical charged balls are suspended from massless threads of length L ,initi init distance d apart. Charge begin to leak out at constant rate and they approach each other with speed V. Then V is proportional to what power of distance X between the two?

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subash · Answer

mgsin¢=F. on solving we get q 2 = (2π€°mg/l)×x =Cx 3. , on differentiating we get 2qdq/dt=3Cx 2 dx/dt, on substuting proportionality of v and c in 1 eqn we get v is proportional to x -1/2

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Two identical charged balls are suspended from massless threads of length L ,initi init distance d apart. Charge begin to leak out at constant rate and they approach each other with speed V. Then V is proportional to what power of distance X between the two?

Two identical charged balls are suspended from massless threads of length L ,initi init distance d apart. Charge begin to leak out at constant rate and they approach each other with speed V. Then V is proportional to what power of distance X between the two?

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Two identical charged balls are suspended from massless threads of length L ,initi init distance d apart. Charge begin to leak out at constant rate and they approach each other with speed V. Then V is proportional to what power of distance X between the two?

Two identical charged balls are suspended from massless threads of length L ,initi init distance d apart. Charge begin to leak out at constant rate and they approach each other with speed V. Then V is proportional to what power of distance X between the two?

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