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Grade: 11
        
Two equal charges of magnitude q each are placed at a distance d apart.Their electrostatic energy is E.A third charge-Q/2 is brought midway between these two charges.The electrostatic energy of this system is now
10 months ago

Answers : (1)

harshin nechooli
121 Points
							
Here the energy refers to the electrostatic potential energy does initially there have a potential energy of k q bhai d then when charge is brought final potential energy after system will change to 5 e
finally   PE = kq÷(d÷2) +kq÷(d÷2) +E. and E= kq÷d
10 months ago
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