Three charges Q,+q,+q are placed at the vertices of a right angled isosceles triangle . The net electrostatic energy of the configuration is zero if Q is equal to

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Khimraj · Answer

Let sides of triangles are a,a, then electrostatic energy will be 2KQq/a 2 +Kqq/2a 2 = 0 Then Q = -q/4. Hope it clears. If you like answer then please approve it.

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Three charges Q,+q,+q are placed at the vertices of a right angled isosceles triangle . The net electrostatic energy of the configuration is zero if Q is equal to

Three charges Q,+q,+q are placed at the vertices of a right angled isosceles triangle . The net electrostatic energy of the configuration is zero if Q is equal to

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Three charges Q,+q,+q are placed at the vertices of a right angled isosceles triangle . The net electrostatic energy of the configuration is zero if Q is equal to

Three charges Q,+q,+q are placed at the vertices of a right angled isosceles triangle . The net electrostatic energy of the configuration is zero if Q is equal to

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