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# The potential difference between A and B is 18V and charge on 2 uF capacitor is 24uC.The value of C is:

Khimraj
3007 Points
3 years ago
The volage across 2$\mu$F capacitor = 24$\mu$C/2$\mu$F = 12 V.
So voltage across 6$\mu$F capacitor = 18 – 12 = 6V
So charge on 6$\mu$F capacitor = 6*6 = 36$\mu$C
So charge on C capacitor = 36 – 24 = 12$\mu$C
So value of C = 12$\mu$C/12V = 1$\mu$F.