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The potential difference between A and B is 18V and charge on 2 uF capacitor is 24uC.The value of C is:

Atreyee Biswas , 7 Years ago
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anser 1 Answers
Khimraj

Last Activity: 7 Years ago

The volage across 2\muF capacitor = 24\muC/2\muF = 12 V.
So voltage across 6\muF capacitor = 18 – 12 = 6V
So charge on 6\muF capacitor = 6*6 = 36\muC
So charge on C capacitor = 36 – 24 = 12\muC
So value of C = 12\muC/12V = 1\muF.
Hope it clears. If you like answer then please approve it.

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