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Six charge are kept at the vertices of a regular hexagon as shown in figure . If magnitude of force applied by +Q on +q charge is F, then net force on the +Q is nF. Find value of `n`

Six charge are kept at the vertices of a regular hexagon as shown in figure . If magnitude of force applied by +Q on +q charge is F, then net force on the +Q is nF. Find value of `n`

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Grade:12th pass

2 Answers

Eshan
askIITians Faculty 2095 Points
5 years ago
The opposite charges sitting on opposite ends of any diagonal will contribute to increase the force in the direction of negative charge.
Hence forces acting on central charge reduces like-
568-1771_Untitled.png
Net force acting vertically downwards=5F+2F-2.5F=4.5F
Net force acting horizontally=
2.5\sqrt{2}F+2\sqrt{3}F=4.5\sqrt{3}F
Hence net force acting on the charge=\sqrt{(4.5F)^2+(4.5\sqrt{3}F)^2}=9F
Rishi Sharma
askIITians Faculty 646 Points
3 years ago
Dear Student,
Please find below the solution to your problem.

If magnitude of force applied by +Q on +q charge =1
net electric force on the +Q is nF
WhenF = ​(1/4πϵ0)*​(q1​q2/r^2)​​
= 3×3q
=nF
or, n=9

Thanks and Regards

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