#### Thank you for registering.

One of our academic counsellors will contact you within 1 working day.

Click to Chat

1800-1023-196

+91-120-4616500

CART 0

• 0
MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping

# Plzzzzzzzzzzzzzzoooooooooooooooooooolkoolook solve question number 7

Pooja
127 Points
one year ago

To find Potential due to a non conducting sphere
total charge inside it be ‘Q’
volumetric charge density be ‘ρ’.
Let R be the radius of the sphere.
We need to calculate potential due to a conducting shell at distance r such that it is inside sphere

We know the relation between volumetric charge density (ρ) and total charge within the volume (Q) :

Q = 4πR33 ρ.......(1)

We also know,

dV = - ∫Edr

We also know the relation between electric field (E) and potential (dV)
Let the distance r from centre  enclose a small sphere with radius r and charge q.

dE=kq/r2

Q/R3 = q/r3     (from eq 1)

dE = kQr/R3

dV = -∫kQr. dr/R3

= - lim[kQr2/2R3]

Integrating above equation and applying limits from r to R

VR - Vr = -kQR2/2R3 + kQr2/2R3

Now VR = kQR2/R3

kQR2/R3 - Vr = kQr2/2R3 - kQR2/2R3
Vr = 3kQR2/2R- kQr2/2R3

=kQ/2R3 (3R2 - r2)

Ans is (A)