0

Guest

Courses New

Please answer 13 question with detailed explanation........ .....thankiu in advance

Please answer 13 question with detailed explanation........
.....thankiu in advance

Question Image
Grade:12th pass

1 Answers

Eshan
askIITians Faculty 2095 Points
5 years ago
Dear student,

Since charge on2\mu Fcapacitor is24\mu C, the voltage across it is12V. Since it is in parallel to capapcitor C, C also has 12V across it.

Since the battery provides 18V, the voltage on6\mu Fcapacitor is18V-12V=6V.
Hence the charge stored on it is36\mu C. This current must have divided into the two capacitors in series. Hence charge stored on C is36\mu C-24\mu C=12\mu C. But potential difference across it is12V. Hence the capacitance C is\dfrac{12\mu C}{12V}=1\mu F

Think You Can Provide A Better Answer ?

Other Related Questions on Electrostatics

View all Questions »

ASK QUESTION

Get your questions answered by the expert for free

Answer and earn gift vouchers

Win Gift vouchers upto Rs 500/-

View courses by askIITians

Design classes One-on-One in your own way with Top IITians/Medical Professionals

Click Here Know More

Complete Self Study Package designed by Industry Leading Experts

Click Here Know More

Live 1-1 coding classes to unleash the Creator in your Child

Click Here Know More

a Complete All-in-One Study package Fully Loaded inside a Tablet!

Click Here Know More