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in a region uniform electric field E=10^3 N/C exists along +y axis .a charged particle (mass =1g, charge =1mC) enters with velocity 10 m/s along +x axis find speed of the particle when displacement along x axis is 10 cm.


3 years ago

Shailendra Kumar Sharma
188 Points
							Assume the particle is moving along X-axis and Along +Y Axis there is an Electric field. It can be assumed a gravitational field. so the force on object will be qE and acceleration along +Y axis will be qE/m a=qE/ma= {1x10-3 * (103)}/(10-3) =103 m/sNow velocity when displacement along x-axis 10cm. time taken in 10 cm travel will be 10cm/10m/s = 0.01s. So the y component of velocity will be Vy=at =1000*(.01) =10m/sSo the velocity of particle will be $\sqrt{100+100} =10\sqrt{2}$  or 14.14 m/s

3 years ago
ankit singh
596 Points
							in a region uniform electric field E=10^3 N/C exists along +y axis .a charged particle (mass =1g, charge =1mC) enters with velocity 10 m/s along +x axis find speed of the particle when displacement along x axis is 10 cm.

2 months ago
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### Course Features

• 110 Video Lectures
• Revision Notes
• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions