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If the two plates of a capacitor are given charge q1 and q2 what will be the electric field in between and to the right and left of the plates?

Sunny Gupta , 8 Years ago
Grade 12th pass
anser 1 Answers
Umakant biswal

Last Activity: 8 Years ago

@ sunny 
you doesnot mention here weather the space between the two plates are empty or filled with a dielectric slab . 
if they are empty , then  by applying the electric field formula 
E= SIGMA / E0 
and calculating u will get 
E= E0 A/ D 
where e0 is the permittivity of free space , a is the area of the plates , and d is the distance between two plates . 
if the spaces are filled with dielectric then 
E= e0 AK /D 
where k is the dielectric constant , and value depend upon the type of dielectric . 
and outside the plates of capacitor the electric field is 0 , 
so, i think right or left its 0 as all over the electric field are same between the plates . 
HOPE IT CLEARS YOUR DOUBT 
IF ANY MORE SPECIFICATION THEN ASK THE QUERY WITH A BIT SPECIFIC 
 

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