hello mam, A charge Q is divided into two parts of qand Q-q if the coulomb repulsion between them when they are seprated is to be maximum the ratio of Q/q should be
? in this answer its given that for maximum forcedF/dq=0.. may i know how this is taken?

Question

Beenu Mathew · Answer

Given a separation r, the force is F = k q (Q-q) / r 2 This is maximum when q (Q-q) has a maximum. The quadratic -q 2 + q Q has a maximum where q = -Q/(-2), so when q/Q = ½ or Q/q=2

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hello mam, A charge Q is divided into two parts of qand Q-q if the coulomb repulsion between them when they are seprated is to be maximum the ratio of Q/q should be ? in this answer its given that for maximum forcedF/dq=0.. may i know how this is taken?

hello mam, A charge Q is divided into two parts of qand Q-q if the coulomb repulsion between them when they are seprated is to be maximum the ratio of Q/q should be
? in this answer its given that for maximum forcedF/dq=0.. may i know how this is taken?

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hello mam, A charge Q is divided into two parts of qand Q-q if the coulomb repulsion between them when they are seprated is to be maximum the ratio of Q/q should be ? in this answer its given that for maximum forcedF/dq=0.. may i know how this is taken?

hello mam, A charge Q is divided into two parts of qand Q-q if the coulomb repulsion between them when they are seprated is to be maximum the ratio of Q/q should be? in this answer its given that for maximum forcedF/dq=0.. may i know how this is taken?

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hello mam, A charge Q is divided into two parts of qand Q-q if the coulomb repulsion between them when they are seprated is to be maximum the ratio of Q/q should be
? in this answer its given that for maximum forcedF/dq=0.. may i know how this is taken?