Thank you for registering.

One of our academic counsellors will contact you within 1 working day.

Please check your email for login details.
MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping

Derive an expression for electric potential at the centre of an equilateral triangle of side 2a when charges of magnitudes q,2q and 3q are placed in the three vertices. Explain in detail.

Derive an expression for electric potential at the centre of an equilateral triangle of side 2a when charges of magnitudes q,2q and 3q are placed in the three vertices. Explain in detail.

Grade:12

1 Answers

Vikas TU
14149 Points
5 years ago
First find the distance b/w the vertices to center of the equ. triangle.
And it will come as:
r (let) = (2/root3)a { a/hypertenuse = cos30}
 
Now  since potential is a scalar quantity only sign matters .i.e all are positive charges.
Therfore net Electric potential at center is:
V net = V1 + V2 + V3
         = kq/r + k(2q)/r + k(3q)/r 
         = 6kq/r
put r
=> 6kq/(2/root3)a
=> 3root3kq/a

Think You Can Provide A Better Answer ?

Provide a better Answer & Earn Cool Goodies See our forum point policy

ASK QUESTION

Get your questions answered by the expert for free