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# charges 2q and -3q are given to two identical metal plates of crossectional area A . the distance between plates is d . find potenfial difference between plates

Abhishek Singh
93 Points
5 years ago
Always remember in this case that the half of the total charges will be at the oute surface of the  plates
i.e = -q/2
so inside of first plate charge is  = 5q/2    and inside of the second plate is -5q/2
THis should be because of induction.
now you calculate electric field   = $\frac{5q}{A\epsilon }$