An object has an excess charge of -1.92x10^-7 C.How many excess electrons does it have?
An object has an excess charge of -1.92x10^-7 C.How many excess electrons does it have?
Bhavya , 6 Years ago
Grade 12
Electrostatics> An object has an excess charge of -1.92x1...
3 Answers
Arun
Dear student
Number of excess electrons = -1.92 * 10^-7 / – 1.6 * 10^-19 = 1.2 * 10^12 electrons
Hope it helps
Regards
Arun (askIITians forum expert)
Approved Last Activity: 6 Years ago
Saurabh Koranglekar
Dear student
Charge = charge of one electron * number of electrons
-1.92*10^(-7)= n (-1.6*10^(-19)
n= 1.2*10^12 electrons
Regards
Charge = charge of one electron * number of electrons
-1.92*10^(-7)= n (-1.6*10^(-19)
n= 1.2*10^12 electrons
Regards
Approved Last Activity: 6 Years ago
Khimraj
This object has a charge of −1.92⋅10−7 C.
Remember that electrons (e−) have a charge of −1.602⋅10−19 C. So here, there exist: -1.92 * 10-7 / – 1.6 * 10-19 = 1.2*1012
Approved Last Activity: 6 Years ago
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