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Grade 12Electrostatics

An object has an excess charge of -1.92x10^-7 C.How many excess electrons does it have?

Profile image of Bhavya
7 Years agoGrade 12
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3 Answers

Profile image of Arun
ApprovedApproved Tutor Answer7 Years ago
Dear student
 
Number of excess electrons = -1.92 * 10^-7 / – 1.6 * 10^-19 = 1.2 * 10^12 electrons
 
Hope it helps
 
Regards
Arun (askIITians forum expert)
Profile image of Saurabh Koranglekar
ApprovedApproved Tutor Answer7 Years ago
Dear student

Charge = charge of one electron * number of electrons
-1.92*10^(-7)= n (-1.6*10^(-19)

n= 1.2*10^12 electrons

Regards
Profile image of Khimraj
ApprovedApproved Tutor Answer7 Years ago

This object has a charge of −1.92⋅10−7 C.

Remember that electrons (e−) have a charge of −1.602⋅10−19 C. So here, there exist: -1.92 * 10-7 / – 1.6 * 10-19 = 1.2*1012

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