# A standing wave pattern is formed when a plane electromagnetic wave from a transmitter falls on a perfect reflector at normal incidence. A receiver kept at a distance d from the reflector and along the line of normal incidence detects a minimum for a signal of frequency, ν = 100 MHz. When the frequency is decreased to ν = 99.9 MHz, the receiver records a maximum. Assuming c = 3 × 10^8 ms−1, the distance d is(A) 75 m (B) 1500 m (C) 3000 m (D) 750 m

Darshit
13 Points
3 years ago
Clearly, in between the receiver and the reflector the following condition is satisfied:
For v = 100 MHz, d = nλ/2; where is ‘n’ is some integer.   ------------------(1)

For v’ = 99.9 MHz, d = (n-1)λ’/2 + λ’/4 [Here, the n would be one less compared to the above case. P.S. – There is no option to upload a picture here so can’t help much with the explanation.]    -------------------------(2)

from (1) and (2)

nλ/2 = (n-1)λ’/2 + λ’/4

nc/v = (n-1)c/v’ + c/2v’

Upon simplification you will get,

n = v/2(v-v’) putting and (1) and simplifying, you get

d = c/4(v-v’) = 750m.   Ans. Option (D)