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A point charge q= -8 nC is located at origin. Find the electric field vector at the point x=1.2m and y= -1.6m.

the self , 7 Years ago
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anser 1 Answers
Khimraj
r = 1.2\hat{i} – 1.6\hat{j}
\hat{r} = r/|r| = (1.2\hat{i} – 1.6\hat{j})/2 = 0.6\hat{i} – 0.8\hat{j}
|r| = 2m
E = KQ\hat{r}/r2
E = 9*109*(-8*10-9)*(0.6\hat{i} – 0.8\hat{j})/4
E = 18( - 0.6\hat{i} + 0.8\hat{j}) N/C
Hope it clears.
Last Activity: 7 Years ago
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