A particle of charge 1 microcoulomb and mass 1 gm moving with velocity 4m/s is subjected to a uniform electric field of magnitude 300 V/m for 10 sec then its final speed cannot be: A] 0.5 B] 4 C] 3 D] 6

Question

Rituraj Tiwari · Answer

Sujit kumar · Answer

Electrostatic force on the charge particle will be

$F=qE=ma$

$a=\frac{qE}{m}=\frac{10^{-6}\times 300}{0.001}=0.3m/s^2$

Now there are two possibility.

1)electric field is in the direction of velocity $\theta=0^o$

$v=u+at=4+0.3\cdot 10=7m/s$

case 2. if electric field is in opposite direction of velocity $\theta=180^o$

$v=u-at=4-0.3\cdot 10=1m/s$

So its final speed can be between 1m/s to 7m/s depending

on the angle between electric field and velocity vector

So, option 0.5 m/s is not possible in 10 sec interval

Hence option (1) is correct

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A particle of charge 1 microcoulomb and mass 1 gm moving with velocity 4m/s is subjected to a uniform electric field of magnitude 300 V/m for 10 sec then its final speed cannot be: A] 0.5 B] 4 C] 3 D] 6

A particle of charge 1 microcoulomb and mass 1 gm moving with velocity 4m/s is subjected to a uniform electric field of magnitude 300 V/m for 10 sec then its final speed cannot be:
A] 0.5 B] 4 C] 3 D] 6

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A particle of charge 1 microcoulomb and mass 1 gm moving with velocity 4m/s is subjected to a uniform electric field of magnitude 300 V/m for 10 sec then its final speed cannot be: A] 0.5 B] 4 C] 3 D] 6

A particle of charge 1 microcoulomb and mass 1 gm moving with velocity 4m/s is subjected to a uniform electric field of magnitude 300 V/m for 10 sec then its final speed cannot be:A] 0.5 B] 4 C] 3 D] 6

2 Answers

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A particle of charge 1 microcoulomb and mass 1 gm moving with velocity 4m/s is subjected to a uniform electric field of magnitude 300 V/m for 10 sec then its final speed cannot be:
A] 0.5 B] 4 C] 3 D] 6