A parallel plate capacitor is charged to a potential of V volts. The battery is then disconnected and the distance between the plates of the capacitor is increased using an insulating handle. The potential difference between the plates of the capacitor will

Question

Arun · Answer

Dear student Charge remains conserved in phenomenon CV = C'V' V' = CV/C' = V/k Hence potential difference decrease and becomes 1/k times of original value.

Admit raj · Answer

As we know C=€oA/d,so if `d` increase

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A parallel plate capacitor is charged to a potential of V volts. The battery is then disconnected and the distance between the plates of the capacitor is increased using an insulating handle. The potential difference between the plates of the capacitor will

A parallel plate capacitor is charged to a potential of V volts. The battery is then disconnected and the distance between the plates of the capacitor is increased using an insulating handle. The potential difference between the plates of the capacitor will

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A parallel plate capacitor is charged to a potential of V volts. The battery is then disconnected and the distance between the plates of the capacitor is increased using an insulating handle. The potential difference between the plates of the capacitor will

A parallel plate capacitor is charged to a potential of V volts. The battery is then disconnected and the distance between the plates of the capacitor is increased using an insulating handle. The potential difference between the plates of the capacitor will

2 Answers

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Other Related Questions on Electrostatics

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