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Grade:

                        

A METAL SURFACE HAS A POSITIVE CHARGE OF 10-9 C HOW MANY ELECTRONS WOULD HAVE BEEN REMOVED FROM THE METAL SURFACE?

6 years ago

Answers : (4)

Roshan
10 Points
							lol. i am also searchng for the answer Lekshmi :P
						
6 years ago
Pushkar Aditya
71 Points
							charge=q=10^-9 C ,     according to quantisation of charge we have,  q = ne ,     n=no. of electrons, e=charge on 1 electron i.e. 1.6 * 10^-19 C,      then n=q/e= 6.25 * 10^-29                   here * stands for multiply.  that`s all.
						
6 years ago
Pushkar Aditya
71 Points
							according to quantisation of charge, q =ne,   q=charge ,n= no. of electrons, e= charge on an electron i.e. 1.6*10^-19,   So     n=q/e= 6.25*10^-29           * stands for multiply     that`s all.
						
6 years ago
kamakshi
24 Points
							The elementary charge is 1.6x10^-19 . Thus to find the number of electrons removed from the surface divide the total charge by the elementary charge i.e. 10^-9/(1.6x10^-19) by using the formula q=ne therefore the final answer will be that 6.25x10^9 electrons have been removed.
						
6 years ago
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