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Grade 12th passElectrostatics

A hollow sphere of radius 2R is charged to V volt and another smaller sphere of radius R is charged to V/2 volt.Then the smaller sphere is placed inside the bigger
sphere without changing the net charge on each sphere.The potential difference between the two spheres would be ?

nikita

8 Years agoGrade 12th pass

1 Answer

Ravneet

8 Years ago

THEORY: inside the hollow sphere the potential at every point is constant and is equal to the potential at the surface

because electric field is zero inside the hollow sphere

new potential of small sphere when placed inside bigger sphere = potential due to bigger sphere + existing potential of the smaller sphere

new potential of smaller sphere = V + V/2 = 3V/2

new potential of bigger sphere = existing potential of bigger sphere + potential due to the smaller sphere ( at distance 2R potential due to small sphere will be V/4)

new potental of bigger sphere = V + V/4 = 5V/4

potental difference=new potential of smaller sphere – new potental of bigger sphere

pootential difference = V/4

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