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A charged cork of mass m suspended by a light string is placed in uniform electric field of strength E = ( i^ + j^ ) * 10 5 N/C. If in equilibrium position tension in string is 2mg/ ( 1 + root3), the angle ‘alpha’ with the vertical is :

A charged cork of mass m  suspended by a light string is placed in uniform electric field of strength E = ( i^ + j^ ) * 10N/C. If in equilibrium position tension in string is 2mg/ ( 1 + root3), the angle ‘alpha’ with the vertical is :

Grade:12

2 Answers

Ankit
askIITians Faculty 165 Points
4 years ago
522-2153_Capture.PNG
Nikhil
13 Points
one year ago
Actually answer is 1st bcoz ( cosa +sina)=1+√3/2 = 1/2+√3/2.. ~cos a =1/2= 60 .. Sina =√3/2=60 ..     Actually in this  F = MA WILL ACT. AND VECTOR COMPONETA ARE RECUIRED

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