If the force between two charged objects is to be left unchanged even though the charge on one of the objects is halved keeping the other the same the original distance of sepration d should be equal to

Dear pallavi

let the force on charged object is q and Q

F=1/4∏ε  qQ/d² 

 now let the q become q/2    and seperation now x

F= 1/4∏ε (q/2)Q/x² 

so 1/4∏ε  qQ/d²   = 1/4∏ε (q/2)Q/x² 

  1/d2 =1/2x²

  x = d/√2

so  seperation between them should be  decrese by = d-d/√2

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