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`        Three charges q,q and -q are placed at the corners of an equilatereal triangle The ratio of the force on a +ve charge to the force on the negative charge will be equal to`
8 years ago

147 Points
```										Dear pallavi bhardwaj

let side of triangle is a
F= 1/4∏ε q2/a2
force on positiive charge = [F2 +F2 + 2FFcos120]1/2
= F
force on negatieve  charge = [F2 +F2 + 2FFcos120]1/2
= F
so ratio =F/F =1:1
Please feel free to post as many doubts on our discussion forum as you can. If you find any question Difficult to understand - post it here and we will get you the answer and detailed solution very quickly. We are all IITians and here to help you in your IIT JEE  & AIEEE preparation.
```
8 years ago
147 Points
```										Dear pallavi bhardwaj

let side of triangle is a
F= 1/4∏ε q2/a2
force on positiive charge = [F2 +F2 + 2FFcos120]1/2
= F
force on negatieve  charge = [F2 +F2 + 2FFcos60]1/2
= F√3
so ratio =F/F√3 =1:√3
Please feel free to post as many doubts on our discussion forum as you can. If you find any question Difficult to understand - post it here and we will get you the answer and detailed solution very quickly. We are all IITians and here to help you in your IIT JEE  & AIEEE preparation.
```
8 years ago
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