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pallavi pradeep bhardwaj Grade: 12
        

Three charges q,q and -q are placed at the corners of an equilatereal triangle The ratio of the force on a +ve charge to the force on the negative charge will be equal to

8 years ago

Answers : (2)

Badiuddin askIITians.ismu Expert
147 Points
										

Dear pallavi bhardwaj

 

6835-344_7662_untitled.JPG

let side of triangle is a

 F= 1/4∏ε q2/a2

 force on positiive charge = [F2 +F2 + 2FFcos120]1/2

                                                = F

 force on negatieve  charge = [F2 +F2 + 2FFcos120]1/2

                                                = F

so ratio =F/F =1:1

Please feel free to post as many doubts on our discussion forum as you can.
 If you find any question Difficult to understand - post it here and we will get you the answer and detailed solution very quickly.
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Askiitians Experts
Badiuddin

8 years ago
Badiuddin askIITians.ismu Expert
147 Points
										

Dear pallavi bhardwaj

 6837-876_7662_untitled.JPG

 

let side of triangle is a

 F= 1/4∏ε q2/a2

 force on positiive charge = [F2 +F2 + 2FFcos120]1/2

                                                = F

 force on negatieve  charge = [F2 +F2 + 2FFcos60]1/2

                                                = F√3

so ratio =F/F√3 =1:√3

Please feel free to post as many doubts on our discussion forum as you can.
 If you find any question Difficult to understand - post it here and we will get you the answer and detailed solution very quickly.
 We are all IITians and here to help you in your IIT JEE  & AIEEE preparation.

 All the best.
 
Regards,
Askiitians Experts
Badiuddin

8 years ago
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