Calculate the time required to deposit 56g of silver from a silver nitrate solution using a current of 4.5A.

n(e) = 0.519 mol 
F = 96,500 C mol^-1

Q = 0.519 x 96,500 = 50,083.5 C

Q = 50,083.5 C   I = 4.5 A 

t = Q/I
t = 50,083.5 ÷ 4.5 = 11,129.67 seconds 
t = 11,129.67 ÷ 60 = 185.5 minutes 
t = 185.5 ÷ 60 = 3.1 hours

WIEGHT DEPOSITED=EQUIVALENT WIEGHT*CURRENT(i)*TIME TAKEN FOR THE DEPOSIT(t)/96500

            AND THUS 45=108*4.5*t/96500