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n(e) = 0.519 mol F = 96,500 C mol-1Q = 0.519 x 96,500 = 50,083.5 CQ = 50,083.5 C I = 4.5 A
t = Q/It = 50,083.5 ÷ 4.5 = 11,129.67 seconds t = 11,129.67 ÷ 60 = 185.5 minutes t = 185.5 ÷ 60 = 3.1 hours
WIEGHT DEPOSITED=EQUIVALENT WIEGHT*CURRENT(i)*TIME TAKEN FOR THE DEPOSIT(t)/96500
AND THUS 45=108*4.5*t/96500
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