Thank you for registering.

One of our academic counsellors will contact you within 1 working day.

Click to Chat

1800-1023-196

+91-120-4616500

CART 0

• 0
MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping

.In the given figure, a bar magnet is quickly moved towards a conducting loop having a capacitor. Predict the polarity of the plates A and B of the capacitor

763 Points
3 years ago
Plate A will be negatively charged and plate B will be positively charged... this is determined by lenz law , which states that, An induced electromotive force (emf) always gives rise to a current whose magnetic field opposes the change in original magnetic flux.
Khimraj
3007 Points
3 years ago
We are viewing from magnet side.
So As N pole comes near the loop. the induced current in coil will be in such direction so it behave N as N.
So direction of current is anticlockwise. So A will be positive and B will be negative.
IMRAN AHMED
13 Points
2 years ago
As According to lenz law direction of induced currrent in the loop is such that it opposes the cause due to which it was induced … Hence in this question on seeing from magnet side (left hand side) we see that magnetic line of forces were   going to Right hand side (inward to the loop )  that means the magnetic field is inward to the loop  Hence the direction of induced current is in such a way that it opposes the direction of magnetic field i.e.( inward to the loop ) Therefore the direction is in anticlockwise direction  and Hence the Plate A and plate B of the capacitor is positive and negative respectively  HOPE THIS HELPS!!!!!!