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A uniform magnetic field B exists in a direction perpendicular to the plane of a square frame made of copper wire. The wire has a diameter of 2mm and a total length of 40cm. The magnetic field changes with time at steady rate dB/dt=0.02Ts^-1. What will be the current induced in the frame? (resistivityof copper=1.7x10^-8 ohm m)
I = e/R = 1/ R (d¢/dt)= 1/R. dBA/dt= A/R.dB/dt= A/(pl/a).dB/dt=A .dB/dt.a/pl= A(dB/dt).πr^2/plSubstitute the values and you get the answer.=9.3×10^-2A=93mA
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