Deepak Patra
Last Activity: 11 Years ago
Sol. A = 40 m2 = 40 * 10^–4
d = 0.1 mm = 1 * 10^–4 m
R = 16 Ω ; emf = 2 V
C = E base 0A/d = 8.85 * 10^-12 * 40 * 10^-4/1 * 10^-4 = 35.4 * 10^-11 F
Now, E = Q/AE base 0 (1 – e^-t/RC)
= 35.4 * 10^-11 */ 2/40 * 10^-4 * 8.85 * 10^-12 (1 – e^1.76)
= 1.655 * 10^-4 = 1.7 * 10^-4 V/m.