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Grade: upto college level
        A moving-coil galvanometer has a 50-turn coil of size 2 cm × 2 cm. It is suspended between the magnetic poles producing a magnetic field of 0.5 T. Find the torque on the coil due to the magnetic field when a current of 20 mA passes through it. 
5 years ago

Answers : (1)

Deepak Patra
askIITians Faculty
471 Points
							Sol. Given θ = 37° d = 10 cm = 0.1 m
We know
M/B base H = 4π/μ base 0 (d^2 - ℓ^2)^2/2d tan θ = 4π/μ base 0*d^4/2d tan θ [As the magnet is short]
= 4π/4π * 10^-7 * (0.1)^3/2 * tan 37° = 0.5 * 0.75 * 1 * 10^-3 * 10^7 = 0.375 * 10^4 * 3.75 * 10^3 A-m^2 T^-1

						
5 years ago
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