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Q.A metal rod AB of length L is placed in a magnetic field as shown in the figure.If the rate of change of B w.r.t time is dB/dt,find the emf produced across AB.
Please help me in solving these types of problems.
Dear Raj,
MY PREVIOUS SOLUTION WAS COMPLETELY INCORRECT. PLEASE IGNORE IT.
Consider a square metal loop of side L whose plane is perpendicular to dB/dt.
Induced emf=area*dB/dt=L2dB/dt,
therefore emf induced across AB=(L2/4)dB/dt
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CHETAN MANDAYAM NAYAKAR
THE CORRECT ANSWER IS (1/4)L2a·(dB/dt)
a is the unit vector perpendicular to the square loop considered in the previous solution to this problem.
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