Can the peak voltage across the inductor be greater than peak voltage of the source in an LCR circuit?

Dear Nikhil Garg, 

At resonance the peak current through circuit is
i=E/R
peak voltage across inductance
VL=wL*(E/R)
=QE
where Q is the quality factor (wL/R). Thus at resonance voltage drop across L is Q times the applies voltage. 
Hence the chief chacterstics of series resonance circuit is 'Voltage magnification'.


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Hello

Nikhil

In a series RLC circuit at resonance, the current is limited only by the resistance of the circuit

If R is small, consisting only of the inductor winding resistance say, then this current will be large. It will drop a voltage across the inductor of

An equal magnitude voltage will also be seen across the capacitor but in antiphase to the inductor. If R can be made sufficiently small, these voltages can be several times the input voltage. The voltage ratio is, in fact, the Q of the circuit,

So there can be possibility the Voltage accross induction become larger than the input voltge...this is called Q-amplification at resonance ...

With regards

Yagya