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Consider the situation as shown in figure the wire PQ has mass m , resistance r and can slide on the smooth horizontal parallel rails separated by a distance l. the resistance of rails is negligible. A uniform magnetic field B exists in the rectangular region and a resistance R connects the rail outside the field region. At t=0the wire PQ is pushed towards the right with a speed V0. Find (a) the current in the loop at an instant when the speed of the wire PQ is V, (b) the acceleration of the wire at this instant, (c) the velocity V as a function of X and (d) the
Maximum distance the wire will move.
Max
.
Dear vikash,
emf induced= Bvl
i= currenr=emf/R=Bvl/R
f=FORCE= ilB=B2vl2/R
a=F/m=B2Vl2/R/m
We are all IITians and here to help you in your IIT JEE preparation. All the best. If you like this answer please approve it.... win exciting gifts by answering the questions on Discussion Forum Sagar Singh B.Tech IIT Delhi sagarsingh24.iitd@gmail.com
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