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You are given three circuit elements X, Y and Z. When the element X is connected across an a.c. source of a given voltage, the current and the voltage are in the same phase. When the element Y is connected in series with X across the source, voltage is ahead of the current in phase by pi/4. But the current is ahead of the voltage in phase by pi/4, when Z is connected in series with X across the source. Identify the circuit elements X, Y, and Z. When all the three elements are connected in series across the same source, determine the impedance of the circuit. Draw a plot of the current versus the frequency of the applied source and mention the significance of this plot.
Dear studentPlease find the links below for reference in understanding the underlying concept for the question and then you will surely be able to solve the problem however if you still wont be able to solve you will be able to identify where the doubt is and we will be happy to help from therehttps://www.askiitians.com/iit-jee-electromagnetic-induction/series-l-r-c-r-circuits/https://www.askiitians.com/revision-notes/physics/alternating-current/Regards
When resistance is connected to AC source then, currentr and voltage remains in same phase, hence element X is resistance.When inductor is conneted with resistance then currnet lags behind the voltage hence Y is the inductor.When capacitor is connected wiith resistance then voltage lags behind the current hence Z is the capacitorWhen these elements are connected together then total impedance of the circuit is Z = sqrt(R^2+(Xl)^2 +Xc^2)Hope this will help
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