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# Use Kirchhoff’s rules to determine the potential difference between the points A and D. When no current flows in the arm BE of the electric network shown in the figure.

Eshan
2 years ago
Since no current is flowing through the arm BE, we can use Kirchoff’s rules along the path ABED.
From A to B, drop in potential=6V
From B to E, since no current flows through the resistor, potential drop=3V
There is no change in potential from E to D. Hence the total potential drop from A to D =9V
Ankit
15 Points
2 years ago
Potential drop from A to B is 6v
Potential drop from B to E is 3v
There is no potential drop between E to D
So by Kirchoff law.    v - 3 - 6 = 0
V=9
Priyanshi soni
41 Points
one year ago
Applying Kirchhoff's rule in the loop AFEBA
we get 6V-2I3+1V-3I3-I2R+3V=0
2I3+3I3+I2 R=10V
I2=0 . So
5I3=10V
I3=I1=2A
Va-Vd=2I3-1V+3l3=2*2-1+3*2=9V
5I
10 months ago
Dear student,
Since no current is flowing through the arm BE, we can use Kirchoff’s rules along the path ABED.From A to B, drop in potential=6VFrom B to E, since no current flows through the resistor, potential drop=3VThere is no change in potential from E to D. Hence the total potential drop from A to D =9V
Hope this helps.
Thanks and regards,
Kushagra