two wires of equal length but different cross sectional area A 1 and A 2 and specific resistance ρ 1 and ρ 2 are joined in parallel .the equivalent specific resistance is given as___(ans:ρ 1 ρ 2 (A 1 +A 2 )/[ρ 1 A 2 +ρ 2 A 1 ])

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Keshav Yadav · Answer

We have length of resistances R1 and R2 = l. Area of cross section A1 and A2 resp of R1 and R2 Specific resistances ρ1 and ρ2 resp of R1 and R2 We have R eq = (R1.R2)/(R1+R2) Where R1= ρ1.l/A1 and R2 = ρ2.l/A2 Putting both values in equation R eq =( ρ1.l/A1).( ρ2.l/A2)/( ρ2.l/A2+ ρ1.l/A1) R eq =l(ρ1.ρ2)/( ρ1.A2+ ρ2.A1) Then we know A eq = A1+A2 So R eq = ρ eq .l/A eq (length is constant overall) So ρ eq = (A1+A2). ρ1.ρ2/( ρ1.A2+ ρ2.A1) Hence proved.

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two wires of equal length but different cross sectional area A 1 and A 2 and specific resistance ρ 1 and ρ 2 are joined in parallel .the equivalent specific resistance is given as___(ans:ρ 1 ρ 2 (A 1 +A 2 )/[ρ 1 A 2 +ρ 2 A 1 ])

two wires of equal length but different cross sectional area A₁ and A ₂ and specific resistance ρ₁and ρ₂are joined in parallel .the equivalent specific resistance is given as___(ans:ρ₁ρ₂(A₁+A₂)/[ρ₁A₂+ρ₂A₁])

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two wires of equal length but different cross sectional area A 1 and A 2 and specific resistance ρ 1 and ρ 2 are joined in parallel .the equivalent specific resistance is given as___(ans:ρ 1 ρ 2 (A 1 +A 2 )/[ρ 1 A 2 +ρ 2 A 1 ])

two wires of equal length but different cross sectional area A1 and A 2 and specific resistance ρ1 and ρ2 are joined in parallel .the equivalent specific resistance is given as___(ans:ρ1ρ2(A1+A2)/[ρ1A2+ρ2A1])

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two wires of equal length but different cross sectional area A₁ and A ₂ and specific resistance ρ₁and ρ₂are joined in parallel .the equivalent specific resistance is given as___(ans:ρ₁ρ₂(A₁+A₂)/[ρ₁A₂+ρ₂A₁])