Falling Behind in Studies? Join Our Performance Improvement Batch. Enroll For Free
One of our academic counsellors will contact you within 1 working day.
Click to Chat
1800-1023-196
+91-120-4616500
CART 0
Use Coupon: CART20 and get 20% off on all online Study Material
Welcome User
OR
LOGIN
Complete Your Registration (Step 2 of 2 )
two wires of equal length but different cross sectional area A 1 and A 2 and specific resistance ρ 1 and ρ 2 are joined in parallel .the equivalent specific resistance is given as___(ans:ρ 1 ρ 2 (A 1 +A 2 )/[ρ 1 A 2 +ρ 2 A 1 ])
We have length of resistances R1 and R2 = l.Area of cross section A1 and A2 resp of R1 and R2Specific resistances ρ1 and ρ2 resp of R1 and R2We have Req = (R1.R2)/(R1+R2)Where R1= ρ1.l/A1 and R2 = ρ2.l/A2Putting both values in equationReq =( ρ1.l/A1).( ρ2.l/A2)/( ρ2.l/A2+ ρ1.l/A1)Req =l(ρ1.ρ2)/( ρ1.A2+ ρ2.A1)Then we know Aeq = A1+A2So Req = ρeq.l/Aeq (length is constant overall)So ρeq = (A1+A2). ρ1.ρ2/( ρ1.A2+ ρ2.A1)Hence proved.
Post Question
Dear , Preparing for entrance exams? Register yourself for the free demo class from askiitians.
points won -