two wires of equal length but different cross sec

Question

two wires of equal length but different cross sectional area A1 and A 2 and specific resistance ρ1 and ρ2 are joined in parallel .the equivalent specific resistance is given as___(ans:ρ1ρ2(A1+A2)/[ρ1A2+ρ2A1])

Keshav Yadav · Accepted Answer

We have length of resistances R1 and R2 = l.Area of cross section A1 and A2 resp of R1 and R2Specific resistances ρ1 and ρ2 resp of R1 and R2We have Req = (R1.R2)/(R1+R2)Where R1= ρ1.l/A1 and R2 = ρ2.l/A2Putting both values in equationReq =( ρ1.l/A1).( ρ2.l/A2)/( ρ2.l/A2+ ρ1.l/A1)Req =l(ρ1.ρ2)/( ρ1.A2+ ρ2.A1)Then we know Aeq = A1+A2So Req = ρeq.l/Aeq (length is constant overall)So ρeq = (A1+A2). ρ1.ρ2/( ρ1.A2+ ρ2.A1)Hence proved.

Electric Current> two wires of equal length but different c...

two wires of equal length but different cross sectional area A₁ and A ₂ and specific resistance ρ₁and ρ₂are joined in parallel .the equivalent specific resistance is given as___(ans:ρ₁ρ₂(A₁+A₂)/[ρ₁A₂+ρ₂A₁])

krishna priya , 8 Years ago

Keshav Yadav

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Electric Current> two wires of equal length but different c...

two wires of equal length but different cross sectional area A1 and A 2 and specific resistance ρ1 and ρ2 are joined in parallel .the equivalent specific resistance is given as___(ans:ρ1ρ2(A1+A2)/[ρ1A2+ρ2A1])

krishna priya , 8 Years ago

Keshav Yadav

LIVE ONLINE CLASSES

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