Two particles A and B each of mass m are attached by a light inextensible string of length 2L.The whole system lies on a smooth horizontal table with B initially at a distance L from A. The particle at end B is projected across the table with speed u perpendicular to AB.Velocity of A after jerk?

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Ayush · Answer

Initial velocity of ball along AB=ucosθAB=ucos⁡θand perpendicular to to AB=usinθAB=usin⁡θWhen the string becomes , but the two bodies would acquire the same velocity along ABBy momentum conservation2mv=mucosθ2mv=mucos⁡θv=ucosθ2v=ucos⁡θ2=u2=u2×4l2−l22l×4l2−l22l=u2=u2×3–√l2l×3l2l=3–√4=34u

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Two particles A and B each of mass m are attached by a light inextensible string of length 2L.The whole system lies on a smooth horizontal table with B initially at a distance L from A. The particle at end B is projected across the table with speed u perpendicular to AB.Velocity of A after jerk?

Two particles A and B each of mass m are attached by a light inextensible string of length 2L.The whole system lies on a smooth horizontal table with B initially at a distance L from A. The particle at end B is projected across the table with speed u perpendicular to AB.Velocity of A after jerk?

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Two particles A and B each of mass m are attached by a light inextensible string of length 2L.The whole system lies on a smooth horizontal table with B initially at a distance L from A. The particle at end B is projected across the table with speed u perpendicular to AB.Velocity of A after jerk?

Two particles A and B each of mass m are attached by a light inextensible string of length 2L.The whole system lies on a smooth horizontal table with B initially at a distance L from A. The particle at end B is projected across the table with speed u perpendicular to AB.Velocity of A after jerk?

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