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Vikas TU · Answer

Let the voltage at junction of capacitor, b/w 2 resistances, b/w 3 resistances and at the negative of E volt be x, E, V1 and 0 respectively. Apply KCl at all the nodes respectively. The first eqn. is already given that is voltage across ccapicitor. which is: x – V2 = 10 volt. At x volt from kcl, the eqn. becomes, 5x = 2V1 + E + 20....................(1) at V1 volt from kcl, 3V1 = x + E...................................(2) at E volt, 3E = x + 2V1....................(3) Solving the three eqns. we get, E = 24 volt.

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the question was asked recently at a test. please answer it asap.

the question was asked recently at a test. please answer it asap.

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