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Grade: 12

                        

The four arms of wheatstone bridge have the following resistanes,AB=100Ω, BC=10 Ω,CD=5 Ω, DA=60 Ω A Galvanometer of 15 Ω resistance is connected across BD. Calculate the current through the galvanometer when 10V is maintained across AC.

The four arms of wheatstone bridge have the following resistanes,AB=100Ω, BC=10 Ω,CD=5 Ω, DA=60 Ω A Galvanometer of 15 Ω resistance is connected across BD. Calculate the current through the galvanometer when 10V is maintained across AC.

4 years ago

Answers : (3)

Saurabh Kumar
askIITians Faculty
2411 Points
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245-1180_ex1.PNG
4 years ago
yohanes
13 Points
							
  1. The four arms of a Wheatstone bridge have the following resistances:
AB = 50Ω, BC = 5Ω, CD = 2Ω, DA = 25Ω. A galvanometer of 10Ω resistance is connected across
BD. If a potential difference of 20V is maintained across AC, using Thevenin’s theorem, calculate the current through the galvanometer and draw the Thevenin and Norton Equivalent circuit
2 years ago
ankit singh
askIITians Faculty
609 Points
							
Considering the mesh ABDA, we have
100I1 + 15Ig – 60I2 = 0
or 20I1 + 3Ig – 12I2 = 0  ——(a)
Considering the mesh BCDB, we have
10 (I1 – Ig) – 5 (I2 + Ig) – 15Ig = 0
10I1 – 30Ig – 5I2 = 0
2I1 – 6Ig – I2 = 0 ——(b)
Considering the mesh ADCEA,
60I2 + 5 (I2 + Ig) = 10
65I2 + 5Ig = 10
13I2 + Ig = 2 ——(c)
Multiplying Eq. (b) by 10
20I1 – 60Ig – 10I2 = 0 ——(d)
From Eqs. (d) and (a) we have
63Ig – 2I2 = 0
I2 = 31.5Ig ——(e)
Substituting the value of I2 into Eq. [(c)], we get
13 (31.5Ig ) + Ig = 2
410.5 Ig = 2
Ig = 4.87 mA.
 
6 months ago
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