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Grade: 12

                        

The four arms of wheatstone bridge have the following resistanes,AB=100Ω, BC=10 Ω,CD=5 Ω, DA=60 Ω A Galvanometer of 15 Ω resistance is connected across BD. Calculate the current through the galvanometer when 10V is maintained across AC.

4 years ago

Answers : (3)

Saurabh Kumar
askIITians Faculty
2411 Points
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245-1180_ex1.PNG
4 years ago
yohanes
13 Points
							
  1. The four arms of a Wheatstone bridge have the following resistances:
AB = 50Ω, BC = 5Ω, CD = 2Ω, DA = 25Ω. A galvanometer of 10Ω resistance is connected across
BD. If a potential difference of 20V is maintained across AC, using Thevenin’s theorem, calculate the current through the galvanometer and draw the Thevenin and Norton Equivalent circuit
one year ago
ankit singh
askIITians Faculty
596 Points
							
Considering the mesh ABDA, we have
100I1 + 15Ig – 60I2 = 0
or 20I1 + 3Ig – 12I2 = 0  ——(a)
Considering the mesh BCDB, we have
10 (I1 – Ig) – 5 (I2 + Ig) – 15Ig = 0
10I1 – 30Ig – 5I2 = 0
2I1 – 6Ig – I2 = 0 ——(b)
Considering the mesh ADCEA,
60I2 + 5 (I2 + Ig) = 10
65I2 + 5Ig = 10
13I2 + Ig = 2 ——(c)
Multiplying Eq. (b) by 10
20I1 – 60Ig – 10I2 = 0 ——(d)
From Eqs. (d) and (a) we have
63Ig – 2I2 = 0
I2 = 31.5Ig ——(e)
Substituting the value of I2 into Eq. [(c)], we get
13 (31.5Ig ) + Ig = 2
410.5 Ig = 2
Ig = 4.87 mA.
 
3 months ago
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