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suppose a body is de accelerating with retardation =2m/sec2 suppose it further reduces to 4 m/sec 2. is it possible that body will not come to rest? mathematically dv/dt=-a ( here a>0) and dv/dt represent rate of change of velocity. upon integration we got v=-at+c (if v=0 then t=0 (suppose) then c=0) now t=a/c .now if c is negative then time is negative which is not possible . is this situation possible


suppose a body is de accelerating with retardation =2m/sec2 suppose it further reduces to 4 m/sec 2. is it possible that body will not come to rest? mathematically dv/dt=-a ( here a>0) and dv/dt represent rate of change of velocity. upon integration we got v=-at+c (if v=0 then t=0 (suppose) then c=0) now t=a/c .now if c is negative then time is negative which is not possible . is this situation possible


Grade:9

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